X^2+0.6x-19.1=0

Solution for X^2+0.6x-19.1=0 equation:

X^2+0.6X-19.1=0

a = 1; b = 0.6; c = -19.1;
Δ = b2-4ac
Δ = 0.62-4·1·(-19.1)
Δ = 76.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{76.76}}{2*1}=\frac{-0.6-\sqrt{76.76}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{76.76}}{2*1}=\frac{-0.6+\sqrt{76.76}}{2}
$